Python function to check ArmStrong Number
In this example, We are going to define a user-defined function to check whether the entered number is Armstrong number or not.
A number is known as Armstrong’s number if the sum of the cube root of each digit of this number regenerates the same number again.
Python function to check Armstrong Number
def armstrong(n):
m = n
sum = 0
while(n != 0):
rem = n % 10
sum += rem**3
n = n//10
return True if sum == m else False
def armstrong(n):
m = n
sum = 0
while(n != 0):
rem = n % 10
sum += rem**3
n = n//10
return True if sum == m else False
Implementation of armstrong function in a Python Program
if __name__ == "__main__":
n = int(input('Enter any number :'))
print('ArmStrong Number ' if(armstrong(n)) else 'Not a Arm Strong Number ')
Hence the whole Python program is
def armstrong(n):
m = n
sum = 0
while(n != 0):
rem = n % 10
sum += rem**3
n = n//10
return True if sum == m else False
if __name__ == "__main__":
n = int(input('Enter any number :'))
print('ArmStrong Number ' if(armstrong(n)) else 'Not a ArmStrong Number ')
Output of the above Program is
Enter any number:6 Not a ArmStrong Number Enter any number :153 ArmStrong Number
